![]() # Find each dict based on 'spam' and 'shrubbery' keys. # Find each dict based on 'spam' key only.Īssert find_dict_in_list(dicts, spam=spam) = dicts I've added a little bit of benchmarking below to illustrate pandas' faster runtimes on a larger scale i.e. # The pandas dataframe allows you to pick out specific values like so:ĭf2 = df = 'Pam') & (df = 7) ]ĭf2 = df # Dict items with the same key are entered into the same respective column. Dictionaries differ from lists primarily in how elements are. A dictionary can also contain a list, and vice versa. What you now deal with is a key-value pair, which is sometimes a more appropriate data structure for many problems instead of a simple list. 4 Answers Sorted by: 62 I did not do any timings, but you probably can't get much better than for d in mydicts: d.update ( (k, 'value3') for k, v in d.iteritems () if v 'value2') Update for Python3 for d in mydicts: d.update ( (k, 'value3') for k, v in d. # Create a data frame, keys are used as column headers. A dictionary can contain another dictionary. For example, if you wanted to list the municipalities of two cities, you. Have you ever tried out the pandas package? It's perfect for this kind of search task and optimized too. Python is very friendly to combining objects, such as creating a dictionary of lists. from random import randintįor _ in range(1000): # number of dicts in the listįor i in range(10): # number of keys for each dictįor dict_ in (x for x in list_dicts if x = 20):įor dict_ in = 20]:įor dict_ in filter(lambda x: x = 20, list_dicts): Please see this graph I calculated: (method names see below).Īll tests done with Python 3.6.4, W7圆4. ![]() The keys per dictionary does not affect speed significantly for large amounts (thousands) of keys. In this tutorial, we will see how we can create a dictionary inside a list and then what are the operations that we can perform.All scale linear with the number of dicts in the list (10x list size -> 10x time).Speed: list comprehension > generator expression > normal list iteration > filter.I tested various methods to go through a list of dictionaries and return the dictionaries where key x has a certain value.
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